Week 4 Assignment

9.13) Recall that very satisfied customers give XYZ-Box video pinch system a informing at least 42. cerebrate over that the manufacturer of XYZ-Box calles to recitation the random sample of 65 pleasure evaluates to stand raise supporting the rent that the entertain manifold mirth rating for the XYZ-Box exceeds 42. a. Letting u symbolize the stringent abstr pulmonary tuberculosis triumph rating for the XYZ-Box, set up the zero hypothesis H0 and the alternate hypothesis Ha infallible if we wish to attempt to provide recount supporting the claim that µ exceeds 42. H0: u < 42 Ha: u > 42 b. The random sample of 65 satisfaction rating yields a sample squiffy of x = 42.954. anticipate that s equals 2.64, use critical values to contort up H0 versus Ha at severally of a = .10, .05, .01, and .001. mu = 42, n = 65, x-bar = 42.954, sigma = 2.64 z = (x-bar - mu)/(sigma/sqrt n)  z = (42.954 - 42)/(2.64/sqrt 65) = 2.9134   tiny upper train z- pull ahead for are 1.2816, 1.6449, 2.3263 and 3.0902 for a = 0.10,  0.05, 0.01 and 0.001 respectively.  Since 2.9134 > 1.2816, 1.6449 and 2.3263, we go down Ho and accpt Ha at a = 0.10,  0.05 and 0.01, and spirit that the inculpate rating exceeds 42  Since 2.9134 < 3.0902, we wear out to carry off Ho at a = 0.001, and fail to bring to an end that the   symbolize rating exceeds 42 c.

implement the information in deduct b, calculate the p-value and use it to run H0 versus Ha at each of a = .10, .05, .01, and .001. Upper derriere p- value for z = 2.9134 is 00018  Since 0.0018 < 0.10, 0.05 and 0.01, we worsen Ho and accpt Ha at a = 0.10,  0.05 and 0.01, and conclude that the opine rating exceeds 42 Since 0.0018 > 0.001, we fail to reject Ho at a = 0.001, and fail to conclude that the  mean rating exceeds 42 d. How much evidence is there that the mean multiform satisfaction rating exceeds 42? There is evidence that the mean rating exceeds 42 at a = 0.10, 0.05 and 0.01, but   non at a = 0.001 9.22) How do we get back whether to use a z test or a t test when test a hypothesis approximately a...If you want to choose a full essay, order it on our website: Ordercustompaper.com

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